2020-II-05 Posted on 12-06-2023 By app.cch 在〈2020-II-05〉中尚無留言 答案:Bf(1+β)–f(1–β)=[3(1+β)2–(1+β)–2]–[3(1–β)2–(1−β)–2]=(3+6β+3β2–1–β–2)–(3–6β+3β2–1+β–2)=10β Same Topic: 2017-II-06 2018-II-07 2021-II-07 2022-II-08 2020, 卷二, 香港中學文憑-數學 Tags:基礎函數