2013-I-02

Ans: $k=\dfrac{h}{3-2h}$
$\begin{array}{rcl}
\dfrac{3}{h}-\dfrac{1}{k} & = & 2 \\
\dfrac{1}{k} & = & \dfrac{3}{h} – 2 \\
\dfrac{1}{k} & = & \dfrac{3-2h}{h} \\
k & = & \dfrac{h}{3-2h}
\end{array}$