2021-II-39 Posted on 02-07-2023 By app.cch No Comments on 2021-II-39 Ans: D Join AD. In ΔCDE, ∠DCE=∠CDF−∠CED(ext. ∠ of Δ)∠DCE=49∘−31∘∠DCE=18∘ In ΔACD, ∠ADC=90∘(∠ in semi-circle)∠CAD=∠CDF(∠ in alt. segment)∠CAD=49∘∠ACE=180∘−∠ADC−∠CAD−∠DCE(∠ sum of Δ)∠ACE=180∘−90∘−49∘−18∘∠ACE=23∘ In ΔABC, ∠BAC=∠ACE(alt. ∠s, AB//EC)∠BAC=23∘∠ABC=90∘(∠ in semi-circle)∠ACB=180∘−∠ABC−∠BAC(∠ sum of Δ)∠ACB=180∘−90∘−23∘∠ACB=57∘ Same Topic: 2019-I-13 2019-II-39 2020-II-39 2021-II-22 2021, HKDSE-MATH, Paper 2 Tags:Properties of Circles