2023-I-04

13-07-2023 app.cch No Comments

Ans: (a)

\frac{- 9}{2} < x < 3

(b)

4

Consider the first inequality, we have
$\begin{array}{rcl} 3 x + 2 & > & \frac{4 x - 5}{2} \\ 2 (3 x + 2) & > & 4 x - 5 \\ 6 x + 4 & > & 4 x - 5 \\ 2 x & > & - 9 \\ x & > & \frac{- 9}{2} \end{array}$

Consider the second inequality, we have

$\begin{array}{rcl} 3 x - 2 & < & 7 \\ 3 x & < & 9 \\ x & < & 3 \end{array}$

Therefore, the overall solution is $\frac{- 9}{2} < x < 3$ .
There are $4$ negative integers satisfying $(*)$ .

2023, HKDSE-MATH, Paper 1 Inequality

Leave a Reply Cancel reply