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2020-II-23

Posted on 16-06-202114-06-2023 By app.cch No Comments on 2020-II-23
Ans: B
We sketch a graph according to the question.

Note that the shortest distance between the lighthouse and the ship is $x\text{ km}$.

$\begin{array}{rcl}
\theta & = & 90^\circ – 60^\circ \\
\theta & = & 30^\circ
\end{array}$

Hence, we have

$\begin{array}{rcl}
\sin \theta & = & \dfrac{x}{50} \\
\sin 30^\circ & = & \dfrac{x}{50} \\
x & = & 50 \sin 30^\circ \\
x & = & 25
\end{array}$

Therefore, the shortest distance between the light house and the ship is $25\text{ km}$.

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2020, HKDSE-MATH, Paper 2 Tags:Trigonometry and Its Applications

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3D Problems (41) Basic Functions (13) Basic Geometry (68) Binomial Theorem (7) Change of Subject (32) Complex Numbers (16) Coordinates (46) Differentiation (16) Equations of Circle (54) Equations of Straight Line (43) Estimations and Errors (35) Factorization (39) Graph of Functions (3) Inequality (39) Integration (15) Laws of Indices (43) Linear Programming (21) Locus (13) Logarithm (34) Mathematical Induction (7) Matrices (4) Mensuration (98) Numeral System (19) Percentage (42) Polynomials (49) Probability (85) Properties of Circles (56) Quadratic Equations and Functions (57) Rate and Ratio (30) Rational Functions (20) Sequences (66) Simultaneous Linear Equations (27) Statistics (122) System of Linear Equations (3) Transformations (44) Trigonometry (M2) (7) Trigonometry and Its Applications (67) Variations (38) Vectors (3)

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