Ans: (a) $A’=(7,2)$, $B’=(5,5)$ (b) Equal
- $A'(7,2)$, $B'(5,5)$.
- The length of $AB$
$\begin{array}{cl}
= & \sqrt{[(-2)-(-5)]^2 + (7-5)^2} \\
= & \sqrt{13}
\end{array}$
The length of $A’B’$
$\begin{array}{cl}
= & \sqrt{(7-5)^2 + (2-5)^2} \\
= & \sqrt{13}
\end{array}$
Therefore, the lengths of $AB$ and $A’B’$ are equal.