Ans: D
Since it is an equilateral triangle, then we have
Since it is an equilateral triangle, then we have
$\begin{array}{rcl}
\sqrt{(1-0)^2 + (b-0)^2} & = & 2 – 0 \\
1 + b^2 & = & 4 \\
b^2 & = & 3 \\
b & = & \pm \sqrt{3}
\end{array}$
