Ans: D
Note that the first term is $2006$ and the common difference is $-4$. Hence, we have
Note that the first term is $2006$ and the common difference is $-4$. Hence, we have
$\begin{array}{rcl}
T(n) & = & 2006 + (n-1)(-4) \\
& = & 2010 – 4n
\end{array}$
Let $T(k)$ be the first negative term.
$\begin{array}{rcl}
T(k) & < & 0 \\
2010 - 4k & < & 0 \\
-4k & < & -2010 \\
k & > & 502.5
\end{array}$
Therefore, $k=503$. Hence, the first negative term
$\begin{array}{rcl}
T(503) & = & 2010 – 4(503) \\
& = & -2
\end{array}$
