2006-II-52

Ans: B
Note that the sample space is

$\begin{array}{|c|c|c|c|} \hline
& F & O & R & T & Y \\ \hline
F & FF & FO & FR & FT & FY \\ \hline
I & IF & IO & IR & IT & IY \\ \hline
F & FF & FO & FR & FT & FY \\ \hline
T & TF & TO & TR & TT & TY \\ \hline
Y & YF & YO & YR & YT & YY \\ \hline
\end{array}$

Hence, the required probability

$\begin{array}{cl}
= & \dfrac{4}{25} \\
= & 0.16
\end{array}$