Ans: D
It is given that $f(x)=x^2-ax+2a$.
It is given that $f(x)=x^2-ax+2a$.
$\begin{array}{rcl}
f(-3) & = & 29 \\
(-3)^2 -a(-3) + 2a & = & 29 \\
9 + 3a +2a & = & 29 \\
5a & = & 20 \\
a & = & 4
\end{array}$