Ans: C
$\begin{array}{rcl}
\alpha + 110^\circ & = & 180^\circ \\
\alpha & = & 70^\circ
\end{array}$
Therefore, the bearing of $B$ from $A$
$\begin{array}{cl}
= & 360^\circ – 70^\circ \\
= & 290^\circ
\end{array}$
