Ans: B
By applying the sine law to the triangle, we have
By applying the sine law to the triangle, we have
$\begin{array}{rcl}
\dfrac{x}{\sin (180^\circ – 80^\circ – 30^\circ)} & = & \dfrac{16}{\sin 80^\circ} \\
x & = & \dfrac{16\sin70^\circ}{\sin 80^\circ} \\
& = & 15.267\ 022\ 31 \\
& \approx & 15
\end{array}$
