Ans: C
Since the circle $C$ touches the $y$-axis, then the radius of $C$ is the positive value of the $x$ coordinate of the centre. i.e. radius $=3$. Hence, we have
Since the circle $C$ touches the $y$-axis, then the radius of $C$ is the positive value of the $x$ coordinate of the centre. i.e. radius $=3$. Hence, we have
$\begin{array}{rcl}
[x-(-3)]^2 + (y-4)^2 & = & (3)^2 \\
(x+3)^2 + (y-4)^2 & = & 9
\end{array}$
