2008-I-01 Posted on 16-06-202121-06-2023 By app.cch No Comments on 2008-I-01 Ans: $ab^3$$\begin{array}{cl} & \dfrac{(ab)^3}{a^2} \\ = & \dfrac{a^3b^3}{a^2} \\ = & a^{3-2} b^3 \\ = & ab^3 \end{array}$ Same Topic: 2006-II-37 2008-II-01 2008-II-39 2011-II-01 2008, HKCEE, Paper 1 Tags:Laws of Indices