- Since $a$, $10$, $b$ and $24$ forms an arithmetics sequence, we have
$\begin{array}{rcl}
b & = & \dfrac{10+24}{2} \\
& = & 17
\end{array}$Also, we have
$\begin{array}{rcl}
10 & = & \dfrac{a+b}{2} \\
10 & = & \dfrac{a+17}{2} \\
20 & = & a + 17 \\
a & = & 3
\end{array}$ -
- The salaries tax charged for the citizen
$\begin{array}{cl}
= & P \times 20\% \\
= & \$ 0.2 P
\end{array}$ - For the salaries tax of a citizen being charged at the standard rate,
$\begin{array}{rcl}
30~000\times 3\% + 30~000\times 10\% + 30~000\times 17\% & & \\
+ (P-172~000-90~000)\times 24\% & \ge & 0.2P \\
0.24P – 53~880 & \ge & 0.2P \\
0.04P & \ge & 53~880 \\
P & \ge & 1~347~000
\end{array}$Therefore, the least net total income of the citizen is $\$1~347~000$.
- The salaries tax charged for the citizen
- According to (b)(ii), the salaries tax payable of Peter
$\begin{array}{cl}
= & 1~400~000 \times 0.2 \\
= & \$280~000
\end{array}$The amount after the 1st month
$\begin{array}{cl}
= & 23~000 \times (1+\dfrac{3\%}{12}) \\
= & \$23~000(1.002~5)
\end{array}$The amount after the 2nd month
$\begin{array}{cl}
= & [23~000 + 23~000(1.002~5)] (1+ \dfrac{3\%}{12}) \\
= & \$[23~000(1.002~5) + 23~000(1.002~5)^2]
\end{array}$Hence, the amount after the 12th month
$\begin{array}{cl}
= & 23~000(1.002~5) + 23~000(1.002~5)^2 + \cdots + 23~000(1.002~5)^{12} \\
= & \dfrac{23~000(1.002~5)(1-(1.002~5)^{12})}{1-1.002~5} \\
= & \$280~526.370~6 \\
> & \$280~000
\end{array}$Therefore, Peter has enough money to pay his salaries tax on the due day.
2008-I-16
Ans: (a) $a=3$, $b=17$ (b) (i) $\$0.2P$ (ii) $\$1\ 347\ 000$ (c) Yes