Ans: C
According to the above figure, we have
$\begin{array}{rcl}
\theta & = & 300^\circ – 270^\circ \\
& = & 30^\circ
\end{array}$
The $x$-coordinate of $P$
$\begin{array}{cl}
= & 2 \times \sin 30^\circ \\
= & 1
\end{array}$
The $y$-coordinate of $P$
$\begin{array}{cl}
= & – 2 \times \cos 30^\circ \\
= & -\sqrt{3}
\end{array}$
Therefore, the coordinates of $P$ are $(1, -\sqrt{3})$.
