Ans: D
I is true. The centre of the circle
I is true. The centre of the circle
$\begin{array}{cl}
= & \left( -\dfrac{-4}{2}, – \dfrac{-8}{2} \right) \\
= & (2, 4)
\end{array}$
II is true. The radius of the circle
$\begin{array}{cl}
= & \sqrt{(2)^2 + (4)^2 – 11} \\
= & \sqrt{9} \\
= & 3
\end{array}$
III is true. The distance between the origin and the centre
$\begin{array}{cl}
= & \sqrt{(2-0)^2 – (4-0)^2} \\
= & \sqrt{20} \\
> & 3
\end{array}$
Therefore, the distance between the origin and the centre is larger than the radius. Hence, the origin lies outside the circle.
