Ans: (a) $A’=(-1,4)$, $B’=(-5,2)$ (b) No
- $A’=(-1,4)$, $B’=(-5,2)$.
-
$\begin{array}{rcl}
m_{AB} & = & \dfrac{2-(-2)}{5-(-1)} \\
& = & \dfrac{2}{3}
\end{array}$Also,
$\begin{array}{rcl}
m_{A’B’} & = & \dfrac{2-4}{-5-(-1)} \\
& = & \dfrac{1}{2}
\end{array}$Since $m_{AB} \times m_{A’B’} \neq -1$, then $AB \not \perp A’B’$.
