2009-II-01 Posted on 16-06-202121-06-2023 By app.cch No Comments on 2009-II-01 Ans: B$\begin{array}{cl} & 2^n \cdot 3^n \\ = & (2\cdot 3)^n \\ = & 6^n \end{array}$ Same Topic: 2006-II-37 2009-I-02 2010-II-39 2011-II-01 2009, HKCEE, Paper 2 Tags:Laws of Indices
