Ans: B
$\begin{array}{rcl}
\dfrac{[(x+6) + (2x+3)]\times 8}{2} & = & 96 \\
4(x+6 + 2x + 3) & = & 96 \\
3x + 9 & = & 24 \\
3x & = & 15 \\
x & = & 5
\end{array}$
$\begin{array}{rcl}
\dfrac{[(x+6) + (2x+3)]\times 8}{2} & = & 96 \\
4(x+6 + 2x + 3) & = & 96 \\
3x + 9 & = & 24 \\
3x & = & 15 \\
x & = & 5
\end{array}$
