Ans: B
$\begin{array}{rcl}
x – 5 & \le & 1-x \\
2x & \le & 6 \\
x & \le & 3
\end{array}$
$\begin{array}{rcl}
x – 5 & \le & 1-x \\
2x & \le & 6 \\
x & \le & 3
\end{array}$
Since $x$ is a positive integer, the least value of $x$ is $1$.
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