Ans: A
$\begin{array}{rcl}
(n-2)\times 180^\circ & = & n \times 144^\circ \\
180^\circ n – 360^\circ & = & 144^\circ n \\
36^\circ n & = & 360^\circ \\
n & = & 10
\end{array}$
$\begin{array}{rcl}
(n-2)\times 180^\circ & = & n \times 144^\circ \\
180^\circ n – 360^\circ & = & 144^\circ n \\
36^\circ n & = & 360^\circ \\
n & = & 10
\end{array}$
