2009-II-47 Posted on 16-06-202121-06-2023 By app.cch No Comments on 2009-II-47 Ans: B Let N be the mid-point of HG. Then the angle between MX and the plane BCHG is ∠XMN. By applying the Pythagoras Theorem to the ΔMNG, we have MN2=MG2+GN2MN=152+82=17 cm Note that XN=6 cm. Consider ΔXMN, we have tan∠XMN=XNMNtanθ=617 Same Topic: 2006-I-17 2006-II-45 2009-I-17 2010-II-28 2009, HKCEE, Paper 2 Tags:3D Problems