Ans: $a^4b^{15}$
$\begin{array}{cl}
& a^{14}\left(\dfrac{b^3}{a^2}\right)^5 \\
= & a^{14} \times \dfrac{b^{3\times 5}}{a^{2\times 5}} \\
= & a^{14}\times \dfrac{b^{15}}{a^{10}} \\
= & a^{14-10}b^{15} \\
= & a^4b^{15}
\end{array}$
$\begin{array}{cl}
& a^{14}\left(\dfrac{b^3}{a^2}\right)^5 \\
= & a^{14} \times \dfrac{b^{3\times 5}}{a^{2\times 5}} \\
= & a^{14}\times \dfrac{b^{15}}{a^{10}} \\
= & a^{14-10}b^{15} \\
= & a^4b^{15}
\end{array}$
