Ans: (a) Mean $=25$, median $=26$, range $=13$ (b) (i) $29$ (ii) $\{25,31,31\}$, $\{26,30,31\}$
- The mean
$\begin{array}{cl}
= & \dfrac{18 + 19 +\cdots + 31 + 31}{22} \\
= & 25
\end{array}$The median
$\begin{array}{cl}
= & \dfrac{26 + 26}{2} \\
= & 26
\end{array}$The range
$\begin{array}{cl}
= & 31 – 18 \\
= & 13
\end{array}$ -
- Let $\mu$ be the mean age of the three new players. Then
$\begin{array}{rcl}
\dfrac{18 + 19 + \cdots + 30 + 3 \mu}{23} & = & 25 \\
488 + 3\mu & = & 575 \\
3\mu & = & 87 \\
\mu & = & 29
\end{array}$Therefore, the mean age of the three new players is $29$.
- $\{25,~31,~31\}$, $\{26,~30,~31\}$.
- Let $\mu$ be the mean age of the three new players. Then