Ans: D
The sum of the squares of the two odd numbers means $x^2 +(x-2)^2$. Four times the product of the two odd numbers means $4x(x-2)$. Hence, according to the question, we have $x^2+(x-2)^2 = 4x(x-2)-2$.
The sum of the squares of the two odd numbers means $x^2 +(x-2)^2$. Four times the product of the two odd numbers means $4x(x-2)$. Hence, according to the question, we have $x^2+(x-2)^2 = 4x(x-2)-2$.
