Ans: C
Let $y=a(x-\alpha)(x-\beta)$ be the function of the given graph, where $\alpha < \beta$.
Let $y=a(x-\alpha)(x-\beta)$ be the function of the given graph, where $\alpha < \beta$.
According to the given figure, the two roots are $-4$ and $-1$. Therefore, $\alpha=-4$ and $\beta = -1$.
Note also that the graph passes through the point $(0,-8)$. Then substitute $(0,-8)$ into $y=a(x-(-4))(x-(-1))$ we have
$\begin{array}{rcl}
-8 & = & a(0+4)(0+1) \\
-8 & = & 4a \\
a & = & -2
\end{array}$
Therefore, the function of the graph is $y=-2(x+1)(x+4)$.
