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2011-II-07

Posted on 16-06-202120-06-2023 By app.cch No Comments on 2011-II-07
Ans: A
A is true. Substitute $y=0$ into the equation of the graph, we have

$\begin{array}{rcl}
25- (x-3)^2 & = & 0 \\
x^2 -6x -16 & = & 0 \\
(x-8)(x+2) & = & 0
\end{array}$

$\therefore x=8 \text{ or } x=-2$.

Therefore, the $x$-intercepts of the graph are $-2$ and $8$.

B is false. Substitute $x=0$ into the equation of the graph, we have

$\begin{array}{rcl}
y & = & 25- (0-3)^2 \\
& = & 16
\end{array}$

Therefore, the $y$-intercept of the graph is $16$.

C is false. The equation of the axis of symmetry of the graph is $x=3$.

D is false. The coordinates of the vertex are $(3,25)$.

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3D Problems (41) Basic Functions (13) Basic Geometry (68) Binomial Theorem (7) Change of Subject (32) Complex Numbers (16) Coordinates (46) Differentiation (16) Equations of Circle (54) Equations of Straight Line (43) Estimations and Errors (35) Factorization (39) Graph of Functions (3) Inequality (39) Integration (15) Laws of Indices (43) Linear Programming (21) Locus (13) Logarithm (34) Mathematical Induction (7) Matrices (4) Mensuration (98) Numeral System (19) Percentage (42) Polynomials (49) Probability (85) Properties of Circles (56) Quadratic Equations and Functions (57) Rate and Ratio (30) Rational Functions (20) Sequences (66) Simultaneous Linear Equations (27) Statistics (122) System of Linear Equations (3) Transformations (44) Trigonometry (M2) (7) Trigonometry and Its Applications (67) Variations (38) Vectors (3)

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