Ans: D
Let $(x,y)$ be the rectangular coordinates of $P$.
Let $(x,y)$ be the rectangular coordinates of $P$.
$\begin{array}{rcl}
\cos 150^\circ & = & \dfrac{x}{2} \\
x & = & 2\cos 150^\circ \\
& = & -\sqrt{3}
\end{array}$
Also,
$\begin{array}{rcl}
\sin 150^\circ & = & \dfrac{y}{2} \\
y & = & 2\sin 150^\circ \\
& = & 1
\end{array}$
Therefore, $P=(-\sqrt{3},1)$.
