Ans: A
$\begin{array}{cl}
& 1~000~010~000~101_2 \\
= & 1\times 2^{12} + 1\times 2^7 +1\times 2^2 + 1\times 2^0 \\
= & 5 + 2^7 + 2^{12}
\end{array}$
$\begin{array}{cl}
& 1~000~010~000~101_2 \\
= & 1\times 2^{12} + 1\times 2^7 +1\times 2^2 + 1\times 2^0 \\
= & 5 + 2^7 + 2^{12}
\end{array}$
