2011SP-II-01 Posted on 16-06-2021 By app.cch No Comments on 2011SP-II-01 Ans: C$\begin{array}{cl} & (3a)^2\cdot a^3 \\ = & 9a^2 \cdot a^3 \\ = & 9a^{2+3} \\ = & 9a^5 \end{array}$ Same Topic: 2011SP-I-01 2018-II-01 2020-II-01 2022-II-02 2011SP, HKDSE-MATH, Paper 2 Tags:Laws of Indices