Ans: C
$\begin{array}{rcl}
5-2x & < & 3 \\ -2x & < & -2 \\ x & > & 1
\end{array}$
$\begin{array}{rcl}
5-2x & < & 3 \\ -2x & < & -2 \\ x & > & 1
\end{array}$
Also,
$\begin{array}{rcl}
4x+8 & > & 0 \\
4x & > & -8 \\
x & > & -2
\end{array}$
Therefore, the overall solution is $x>1$.
