Ans: D
$\begin{array}{rcl}
2x & = & 3y \\
y & = & \dfrac{2}{3}x
\end{array}$
$\begin{array}{rcl}
2x & = & 3y \\
y & = & \dfrac{2}{3}x
\end{array}$
Also,
$\begin{array}{rcl}
x & = & 2z \\
z & = & \dfrac{1}{2} x
\end{array}$
Hence, we have
$\begin{array}{rcl}
(x+z):(x+y) & = & (x+\dfrac{1}{2}x) : (x+\dfrac{2}{3}x) \\
& = & \dfrac{3}{2}x : \dfrac{5}{3}x \\
& = & 9:10
\end{array}$
