Ans: B
Consider the area of $ABCD$,
Consider the area of $ABCD$,
$\begin{array}{rcl}
DT \times 9 & = & 36 \\
DT & = & 4 \mbox{ cm}
\end{array}$
Note that $AB=CD$.
$\because AT:TB=1:2$ and $AB=9\mbox{ cm}$,
$\therefore AT=3\mbox{ cm}$.
$\begin{array}{rcl}
AD & = & \sqrt{3^2+4^2} \\
& = & 5 \mbox{ cm}
\end{array}$
Hence, the perimeter of $ABCD$
$\begin{array}{cl}
= & 2(9+5) \\
= & 28 \mbox{ cm}
\end{array}$
