Ans: B
$\begin{array}{cl}
& \dfrac{1}{2-x}+\dfrac{x-1}{(x-2)^2} \\
= & \dfrac{1}{2-x}+\dfrac{x-1}{(2-x)^2} \\
= & \dfrac{(2-x)+(x-1)}{(2-x)^2} \\
= & \dfrac{1}{(2-x)^2}
\end{array}$
$\begin{array}{cl}
& \dfrac{1}{2-x}+\dfrac{x-1}{(x-2)^2} \\
= & \dfrac{1}{2-x}+\dfrac{x-1}{(2-x)^2} \\
= & \dfrac{(2-x)+(x-1)}{(2-x)^2} \\
= & \dfrac{1}{(2-x)^2}
\end{array}$
