2011SP-II-33 Posted on 16-06-202119-06-2023 By app.cch No Comments on 2011SP-II-33 Ans: A$\begin{array}{cl} & 1~0100~1000~1001_2 \\ = & 2^{12}+2^{10}+2^7+2^3+2^0 \\ = & 2^{12}+2^{10}+137 \end{array}$ Same Topic: 2012-II-33 2013-II-33 2015-II-33 2016-II-33 2011SP, HKDSE-MATH, Paper 2 Tags:Numeral System