Ans: A
By sine law, we have
By sine law, we have
$\begin{array}{rcl}
\dfrac{x}{\sin 56^\circ} & = & \dfrac{y}{\sin (180^\circ-47^\circ-56^\circ)} \\
\dfrac{x}{\sin 56^\circ} & = & \dfrac{y}{\sin 77^\circ} \\
y & = & \dfrac{x\sin 77^\circ}{\sin 56^\circ}
\end{array}$