Ans: (a) $x<\dfrac{24}{5}$ (b) $4$
-
$\begin{array}{rcl}
\dfrac{4x+6}{7} & > & 2(x-3) \\
4x+6 & > & 14x-42 \\
-10x & > & -48 \\
x & < & \dfrac{24}{5} \end{array}$Also,
$\begin{array}{rcl}
2x-10 & \le & 0 \\
x & \le & 5
\end{array}$$\therefore$ the required range is $x<\dfrac{24}{5}$.
- $4$
