2012-II-15

Ans: A
In

Δ A D C

$\begin{array}{rcl} A C & = & \sqrt{8^{2} + 6^{2}} \\ = & 10 cm \end{array}$

In $Δ A B C$ ,

$\begin{array}{rcl} A B & = & \sqrt{26^{2} - 10^{2}} \\ = & 24 cm \end{array}$

Therefore, the area of quadrilateral $A B C D$

$\begin{array}{cl} = & \frac{6 \times 8}{2} + \frac{10 \times 24}{2} \\ = & 144 {cm}^{2} \end{array}$

2012, HKDSE-MATH, Paper 2 Mensuration