Ans: C
Join $OB$.
Join $OB$.
$\begin{array}{rcl}
\mbox{reflex }\angle BOD & = & 2\times \angle BCD \\
& = & 2 \times 114^\circ \\
& = & 228^\circ
\end{array}$
Therefore, we have
$\begin{array}{rcl}
\angle BOD & = & 360^\circ-228^\circ \\
& = & 132^\circ
\end{array}$
In $OBCD$,
$\begin{array}{rcl}
\angle OBC & = & 360^\circ – 132^\circ-114^\circ-42^\circ \\
& = & 72^\circ
\end{array}$
In $\Delta OAB$, since $OA$ and $OB$ are radii, then we have
$\begin{array}{rcl}
\angle OBA & = & \angle OAB \\
& = & 28^\circ
\end{array}$
Therefore, we have
$\begin{array}{rcl}
\angle ABC & = & 28^\circ + 72^\circ \\
& = & 100^\circ
\end{array}$
