2012-II-27 Posted on 16-06-2021 By app.cch No Comments on 2012-II-27 Ans: AThe required probability $\begin{array}{cl} = & \dfrac{2}{10} \\ = & \dfrac{1}{5} \end{array}$ Same Topic: 2012-I-16 2012-II-28 2012-II-43 2012-II-44 2012, HKDSE-MATH, Paper 2 Tags:Probability