Ans: B
The mean $\overline{x}$
The mean $\overline{x}$
$\begin{array}{cl}
= & \dfrac{2\times0+8\times1+4\times2+6\times3+2\times4}{2+8+4+6+2} \\
= & \dfrac{21}{11}
\end{array}$
The standard deviation
$\begin{array}{cl}
= & \sqrt{\dfrac{2(0-\overline{x})^2+\ldots+2(4-\overline{x})^2}{22}} \\
= & 1.16
\end{array}$
