Ans: B
The required number
The required number
$\begin{array}{cl}
= & C^{20}_5 – C^{12}_5 \\
= & 14~712
\end{array}$
Resources for HKDSE Mathematics
Resources for HKDSE Mathematics
$\begin{array}{cl}
= & C^{20}_5 – C^{12}_5 \\
= & 14~712
\end{array}$
