Ans: (a) Yes (b) $196$
- Note that the angle between $AO$ and the polar axis is $157^\circ$. Note also that the acute angle between $CO$ and the polar axis is $360^\circ – 337^\circ=23^\circ$.
Then $\angle AOC=157^\circ+23^\circ=180^\circ$.
Therefore, $A$, $O$ and $C$ are collinear.
- Note that $\angle BOA = 247^\circ-157^\circ=90^\circ$.
Therefore the area of $\Delta ABC$
$\begin{array}{cl}
= & \dfrac{1}{2}(13+15)(14) \\
= & 196
\end{array}$
