Ans: A
$\begin{array}{rcl}
4x & > & x-3 \\
3x & > & -3 \\
x & > & -1
\end{array}$
$\begin{array}{rcl}
4x & > & x-3 \\
3x & > & -3 \\
x & > & -1
\end{array}$
Also,
$\begin{array}{rcl}
3-x & < & x+7 \\
-2x & < & 4 \\
x & > & -2
\end{array}$
Therefore, the overall solution is $x>-2$.
