Ans: D
In $\Delta ABC$,
In $\Delta ABC$,
$\because AB=BC$,
$\therefore \angle BCA = \angle BAC=64^\circ$.
$\begin{array}{rcl}
\angle ABC & = & 180^\circ-64^\circ-64^\circ \\
& = & 52^\circ
\end{array}$
$\because AB//CE$,
$\therefore \angle DCE = \angle ABC = 52^ \circ$.
In $\Delta DCE$,
$\because CD = DE$,
$\therefore \angle DEC= \angle DCE = 52^\circ$.
$\begin{array}{rcl}
\angle CDE & = & 180^\circ – 52^\circ – 52^\circ \\
& = & 76^\circ
\end{array}$
