2012PP-II-43 Posted on 16-06-2021 By app.cch No Comments on 2012PP-II-43 Ans: BThe required probability $\begin{array}{cl} = & \dfrac{9!}{10!} \\ = & \dfrac{1}{10} \end{array}$ Same Topic: 2012PP-I-16 2012PP-II-28 2016-I-09 2021-I-15 2012PP, HKDSE-MATH, Paper 2 Tags:Probability