Ans: B
Note that $b$ is the $y$-intercept of the graph. Therefore $b= -10$. Sub. $x=1$ into the function, we have
Note that $b$ is the $y$-intercept of the graph. Therefore $b= -10$. Sub. $x=1$ into the function, we have
$\begin{array}{rcl}
0 & = & -2(1)^2 + a(1) -10 \\
a & = & 12
\end{array}$
Hence, we have $y=-2x^2+12x-10$. Then the equation of the axis of symmetry of the graph is
$\begin{array}{rcl}
x & = & -\dfrac{12}{2(-2)} \\
x & = & 3
\end{array}$
