Ans: D
Since $f(x)$ is divisible by $x+1$, we have
Since $f(x)$ is divisible by $x+1$, we have
$\begin{array}{rcl}
f(-1) & = & 0 \\
(-1)^{13} – 2(-1) + k & = & 0 \\
k & = & -1
\end{array}$
The required remainder
$\begin{array}{rcl}
f(1) & = & (1)^{13}-2(1) -1 \\
& = & -2
\end{array}$
