Ans: B
Since the mode is $14$, there are at least three $14$ in the nine number. With loss of generality, let $x=y=14$. Then consider the mean, we have
Since the mode is $14$, there are at least three $14$ in the nine number. With loss of generality, let $x=y=14$. Then consider the mean, we have
$\begin{array}{rcl}
\dfrac{14+6+4+5+7+5+14+14+z}{9} & = & 8 \\
69 + z & = & 72 \\
z & = & 3
\end{array}$
Then rearrange the nine number in ascending order, we have
\begin{equation*}
3,~4,~5,~5,~6,~7,~14,~14,~14
\end{equation*}
Therefore, the median is $6$.
